Re: Korrektur: Quadrat der Erdkreisfrequenz w² 10^-9 statt 10^9 - ergibt 10^29 J

Geschrieben von AlexP am 10. Februar 2007 11:30:46:

Als Antwort auf: Korrektur: Quadrat der Erdkreisfrequenz w² 10^-9 statt 10^9 - ergibt 10^29 J geschrieben von Georg am 10. Februar 2007 11:16:15:

Deine Rechnung stimmt noch immer nicht, die Geschwindigkeit ist immer noch Faktor 1000 zu hoch.

Nehmen wir den Impact-Calculator und schauen mal:

Your Inputs:
Distance from Impact: 100.00 km = 62.10 miles
Projectile Diameter: 500000.00 m = 1640000.00 ft = 310.50 miles
Projectile Density: 3000 kg/m3
Impact Velocity: 70.00 km/s = 43.47 miles/s
Impact Angle: 45 degrees
Target Density: 2750 kg/m3
Target Type: Crystalline Rock

Energy:
Energy before atmospheric entry: 4.81 x 10^29 Joules = 1.15 x 1014 MegaTons TNT
The average interval between impacts of this size is longer than the Earth's age.
Such impacts could only occur during the accumulation of the Earth, between 4.5 and 4 billion years ago.
Major Global Changes:
The Earth is not strongly disturbed by the impact and loses negligible mass.
The impact does not make a noticeable change in the Earth's rotation period or the tilt of its axis.
The impact does not shift the Earth's orbit noticeably.
Crater Dimensions:
What does this mean?
Transient Crater Diameter: 2430 km = 1510 miles
Transient Crater Depth: 861 km = 535 miles
Final Crater Diameter: 6750 km = 4190 miles
Final Crater Depth: 4.2 km = 2.61 miles
The final crater is replaced by a large, circular melt province.
The volume of the target melted or vaporized is 3.03e+09 km3 = 7.26e+08 miles3
Melt volume = 1.6 times the crater volume
At this size, the crater forms in its own melt pool.

http://www.lpl.arizona.edu/~marcus/cgi-bin/crater.cgi?dist=100&distanceUnits=1&diam=500&diameterUnits=2&pdens=&pdens_select=3000&vel=70&velocityUnits=1&theta=45&wdepth=&wdepthUnits=1&tdens=2750

Auch wenn der die Energie hat, macht der doch recht "wenig"...

cu AlexP

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